Question

complete the data table below by filling in the missing data.
symbol
name fluorine - 19
protons type only a number!
neutrons type only a number!
electrons type only a number!
atomic mass amu type only a number, round to 2 decimal places!
abundance % type only a number exactly as written in the simulation (or trace if thats what it says)!
stable or unstable type stable or unstable

Explanation:

Step1: Find the number of protons

The atomic number is equal to the number of protons. For \(_{9}^{19}\text{F}\), the atomic number is \(9\). So the number of protons is \(9\).

Step2: Find the number of neutrons

The mass number is \(19\). Using the formula \(n = A - Z\) (where \(A\) is the mass number and \(Z\) is the atomic number), we have \(n=19 - 9=10\).

Step3: Find the number of electrons

For a neutral atom, the number of electrons is equal to the number of protons. So the number of electrons is \(9\).

Step4: Find the atomic mass

The mass number of fluorine - 19 is \(19.00\) amu (since it's a single isotope with mass number \(19\)).

Step5: Find the abundance

Fluorine - 19 is the only stable isotope of fluorine, so its abundance is \(100\%\).

Step6: Determine stability

Fluorine - 19 is a stable isotope.

Answer:

Protons: \(9\)
Neutrons: \(10\)
Electrons: \(9\)
Atomic Mass: \(19.00\)
Abundance: \(100\)
Stable or Unstable: stable