Question

1. complete the chart below:

xef4\tpcl5\tso2
number of lone pairs of electrons associated with central atom (lp)\t2
lewis structure diagram\tf - xe - f
with two lone pairs
number of electron groups associated with the central atom (eg)
geometric arrangement (ga)
molecular shape (ms)
bond angle(s)
overall dipole (yes/no •—\tif yes, include below)
3d drawing

Explanation:

Step1: Analyze XeF₄

Central Xe: 8 valence e⁻, 4 bonded to F (4×2=8 e⁻ shared), so LP = (8-4)/2 = 2. EG = 4 bonds + 2 LP = 6 (octahedral GA). MS: square planar (2 LP opposite). Bond angles: 90° (F-Xe-F). Dipole: no (symmetric).

Step2: Analyze PCl₅

Central P: 5 valence e⁻, 5 bonded to Cl (no LP). EG = 5 bonds = 5 (trigonal bipyramidal GA). MS: same as GA. Bond angles: 120° (equatorial), 90° (axial-equatorial). Dipole: no (symmetric).

Step3: Analyze SO₂

Central S: 6 valence e⁻, 2 double bonds to O (4 e⁻ shared), LP = (6-4)/2 = 1. EG = 2 bonds + 1 LP = 3 (trigonal planar GA). MS: bent. Bond angle: ~120°. Dipole: yes (asymmetric).

Answer:

Property	XeF₄	PCl₅	SO₂
Lewis Structure	Xe with 4 F bonds + 2 LP	P with 5 Cl bonds	S with 2 O double bonds + 1 LP
EG	6	5	3
GA	Octahedral	Trigonal bipyramidal	Trigonal planar
MS	Square planar	Trigonal bipyramidal	Bent
Bond angle(s)	90°	120° (equatorial), 90° (axial-equatorial)	~120°
Overall dipole	No	No	Yes
3D drawing	Square planar (Xe center, F at corners, LP top/bottom)	Trigonal bipyramidal (P center, 3 Cl equatorial, 2 Cl axial)	Bent (S center, O atoms at angle, LP on S)