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compare the probability of winning when playing regular defense with th…

Question

compare the probability of winning when playing regular defense with the probability of winning when playing prevent defense. draw a conclusion based on your results.
a. ( p(\text{win} | \text{regular}) = 0.76 )
( p(\text{win} | \text{prevent}) = 0.58 )
conclusion: you are more likely to win by playing regular defense.
b. ( p(\text{win} | \text{regular}) = 0.36 )
( p(\text{win} | \text{prevent}) = 0.64 )
conclusion: you are more likely to win by playing regular defense.
c. ( p(\text{win} | \text{regular}) = 0.36 )
( p(\text{win} | \text{prevent}) = 0.64 )
conclusion: you are more likely to win by playing prevent defense.
d. ( p(\text{win} | \text{regular}) = 0.76 )

Explanation:

Step1: Calculate \(P(\text{win}|\text{regular})\)

The formula for conditional probability is \(P(A|B)=\frac{P(A\cap B)}{P(B)}\). Here, for \(P(\text{win}|\text{regular})\), \(n(\text{win}\cap\text{regular}) = 38\) and \(n(\text{regular})=50\). So \(P(\text{win}|\text{regular})=\frac{38}{50}=0.76\).

Step2: Calculate \(P(\text{win}|\text{prevent})\)

For \(P(\text{win}|\text{prevent})\), \(n(\text{win}\cap\text{prevent}) = 29\) and \(n(\text{prevent}) = 50\). So \(P(\text{win}|\text{prevent})=\frac{29}{50}=0.58\).

Step3: Compare the probabilities

Since \(0.76>0.58\), we conclude that you are more likely to win by playing regular defense.

Answer:

A. \( P(\text{win}|\text{regular}) = 0.76\), \(P(\text{win}|\text{prevent}) = 0.58\). Conclusion: You are more likely to win by playing regular defense.