Question

a coin and a six-sided die are tossed.
event a: the coin lands on tails.
event b: the die does not land on a 1.
what is the probability that both events will occur?
\\(p(a \text{ and } b) = \quad\\%\\)
for independent events: \\(p(a \text{ and } b) = p(a) \cdot p(b)\\)
round your answer to the nearest whole percent.

Explanation:

Calculate the probability of Event A

$$ P(A) = \frac{1}{2} = 0.5 $$

Calculate the probability of Event B

$$ P(B) = 1 - \frac{1}{6} = \frac{5}{6} \approx 0.8333 $$

Calculate the joint probability and convert to percent

$$
LATEXBLOCK0
$$

Answer:

A coin and a six-sided die are tossed.
Event A: The coin lands on tails.
Event B: The die does NOT land on a 1.

What is the probability that both events will occur?

\(P(A \text{ and } B) =\) <blank>42</blank>%