QUESTION IMAGE
Question
classifying chemical reactions practice
synthesis
- two or more simple substances combine to form a single, more complex product.
(general form: a+b→ab)
decomposition
- a single compound breaks down into two or more simpler substances. (general form:
ab→a+b)
combustion
- a substance (usually a hydrocarbon) rapidly reacts with oxygen (o2), producing heat,
light, and typically forming carbon dioxide (co2) and water (h2o). (general form for
hydrocarbons: cxhy+o2→co2+h2o)
single replacement
- one element replaces another element in a compound. a more reactive element takes
the place of a less reactive element. (general form: a+bc→ac+b or a+bc→ba+c)
double replacement
- the positive ions (cations) of two different ionic compounds exchange places, often
resulting in the formation of a precipitate, a gas, or water. (general form:
ab+cd→ad+cb)
please classify each of the following reaction as a synthesis (s), decomposition (d),
combustion (c), single replacement (sr), or double replacement (dr). if a reaction can be
classified as more than one type, include both.
Step1: Analyze reaction 1
Two substances \(Na\) and \(Cl_2\) combine to form \(NaCl\).
Step2: Analyze reaction 2
A single compound \(H_2O\) breaks down into \(H_2\) and \(O_2\).
Step3: Analyze reaction 3
Hydrocarbon \(CH_4\) reacts with \(O_2\) to form \(CO_2\) and \(H_2O\).
Step4: Analyze reaction 4
\(Zn\) replaces \(H\) in \(HCl\).
Step5: Analyze reaction 5
Cations \(Ag^+\) and \(Na^+\) exchange places.
Step6: Analyze reaction 6
\(KClO_3\) breaks down into \(KCl\) and \(O_2\).
Step7: Analyze reaction 7
Cations \(Ba^{2 + }\) and \(H^+\) exchange places.
Step8: Analyze reaction 8
Two substances \(Fe\) and \(O_2\) combine to form \(Fe_2O_3\).
Step9: Analyze reaction 9
Hydrocarbon \(C_2H_6\) reacts with \(O_2\) to form \(CO_2\) and \(H_2O\).
Step10: Analyze reaction 10
\(Cu\) replaces \(Ag\) in \(AgNO_3\).
Step11: Analyze reaction 11
\(CaCO_3\) breaks down into \(CaO\) and \(CO_2\).
Step12: Analyze reaction 12
Cations \(Al^{3 + }\) and \(Ba^{2 + }\) exchange places.
Step13: Analyze reaction 13
Hydrocarbon \(C_6H_{12}O_6\) reacts with \(O_2\) to form \(CO_2\) and \(H_2O\).
Step14: Analyze reaction 14
\(Mg\) replaces \(Fe\) in \(Fe_2O_3\).
Step15: Analyze reaction 15
Two substances \(SO_3\) and \(H_2O\) combine to form \(H_2SO_4\).
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- \(S\)
- \(D\)
- \(C\)
- \(SR\)
- \(DR\)
- \(D\)
- \(DR\)
- \(S\)
- \(C\)
- \(SR\)
- \(D\)
- \(DR\)
- \(C\)
- \(SR\)
- \(S\)