Question

the claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/ml found for nonsmokers. (cotinine is used as a biomarker for exposure to nicotine.) the sample size is ( n = 825 ) and the test statistic is ( t = 57.098 ). use technology to find the p - value. based on the result, what is the final conclusion? use a significance level of 0.01

state the null and alternative hypotheses

( h_0:mu=2.84 )
( h_1:mu>2.84 )
(type integers or decimals. do not round.)

the test statistic is
(round to two decimal places as needed.)

Explanation:

Step1: Identify the test statistic value

The problem states that the test statistic \(t = 57.098\).

Step2: Round the test statistic

We need to round \(57.098\) to two decimal places. Looking at the third - decimal digit \(8\) (since \(57.098\)), using the rounding rule (if the digit is \(5\) or more, we round up the previous digit). So \(57.098\approx57.10\)

Answer:

The test statistic is \( t = 57.098\approx57.10\) (rounded to two decimal places)