Question

chemistry unit 3 common assessment
question 8/11
8 what is the correct lewis dot structure for the oxygen atom (o)?
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d

Explanation:

Step1: Determine the number of valence electrons

Oxygen has an atomic number of 8. Its electron configuration is \(1s^{2}2s^{2}2p^{4}\). The valence electrons are in the \(2s\) and \(2p\) orbitals. The number of valence electrons is \(6\).

Step2: Draw the Lewis dot structure

In a Lewis dot structure, each dot represents a valence electron. We place the dots around the symbol of the element (in this case, \(O\)). We start by placing one dot on each side (up, down, left, right) and then pair them up. For 6 valence electrons, we have two pairs and two unpaired electrons.

Answer:

A. Option Text