chemistry study guide
part 1- balance the following equations. also, classify them in as many ways possible.
1. h₂o₂ h₂ + o₂
2. kbr + h₃po₄ k₃po₄ + hbr
3. c₂h₅oh + o₂ co₂ + h₂o
4. mno₂ + mg mn + mgo
5. cac₂ + h₂o ca(oh)₂ + c₂h₂

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Accepted Answer

# Explanation:
## Step1: Balance the first equation
For $H_2O_2
ightarrow H_2 + O_2$, we can use the trial - and - error method. The balanced equation is $H_2O_2
ightarrow H_2+O_2$ (already balanced). Classification: Decomposition reaction (a single compound breaks down into two simpler substances).
## Step2: Balance the second equation
For $KBr + H_3PO_4
ightarrow K_3PO_4+HBr$.
Count the number of $K$ atoms: On the left, there is $1$ $K$ in $KBr$, on the right, there are $3$ $K$ in $K_3PO_4$. So we put a coefficient of $3$ in front of $KBr$.
$3KBr + H_3PO_4
ightarrow K_3PO_4 + 3HBr$. Classification: Double - displacement reaction (the cations and anions of two compounds exchange places).
## Step3: Balance the third equation
For $C_2H_5OH+O_2
ightarrow CO_2 + H_2O$.
Count the number of $C$ atoms: There are $2$ $C$ in $C_2H_5OH$, so we put a coefficient of $2$ in front of $CO_2$.
Count the number of $H$ atoms: There are $6$ $H$ in $C_2H_5OH$, so we put a coefficient of $3$ in front of $H_2O$.
Now, for $O$ atoms: On the left, we have $1$ (from $C_2H_5OH$) $+x$ (from $O_2$), on the right, we have $2\times2 + 3\times1=7$. So $x = 3$. The balanced equation is $C_2H_5OH+3O_2
ightarrow 2CO_2+3H_2O$. Classification: Combustion reaction (a substance reacts with oxygen to produce carbon dioxide and water).
## Step4: Balance the fourth equation
For $MnO_2+Mg
ightarrow Mn+MgO$.
Count the number of $O$ atoms: There are $2$ $O$ in $MnO_2$, so we put a coefficient of $2$ in front of $MgO$. Then, for $Mg$ atoms, we put a coefficient of $2$ in front of $Mg$. The balanced equation is $MnO_2 + 2Mg
ightarrow Mn+2MgO$. Classification: Single - displacement reaction (a more reactive element displaces a less reactive element from its compound).
## Step5: Balance the fifth equation
For $CaC_2+H_2O
ightarrow Ca(OH)_2 + C_2H_2$.
Count the number of $O$ atoms: There are $2$ $O$ in $Ca(OH)_2$, so we put a coefficient of $2$ in front of $H_2O$. The balanced equation is $CaC_2+2H_2O
ightarrow Ca(OH)_2 + C_2H_2$. Classification: Hydrolysis reaction (a compound reacts with water).

# Answer:
1. Balanced equation: $H_2O_2
ightarrow H_2+O_2$. Classification: Decomposition reaction.
2. Balanced equation: $3KBr + H_3PO_4
ightarrow K_3PO_4 + 3HBr$. Classification: Double - displacement reaction.
3. Balanced equation: $C_2H_5OH+3O_2
ightarrow 2CO_2+3H_2O$. Classification: Combustion reaction.
4. Balanced equation: $MnO_2 + 2Mg
ightarrow Mn+2MgO$. Classification: Single - displacement reaction.
5. Balanced equation: $CaC_2+2H_2O
ightarrow Ca(OH)_2 + C_2H_2$. Classification: Hydrolysis reaction.

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QUESTION IMAGE

Question

Explanation:

Step1: Balance the first equation

Step2: Balance the second equation

Step3: Balance the third equation

Step4: Balance the fourth equation

Step5: Balance the fifth equation

Answer: