QUESTION IMAGE
Question
a chemist measures the energy change \\( \delta h \\) during the following reaction:
\\( \mathrm { cl } _ { 2 } ( g ) + \mathrm { h } _ { 2 } ( g ) \
ightarrow 2 \mathrm { hcl } ( g ) \quad \delta h = - 184. \mathrm { kj } \\)
use the information to answer the following questions.
| this reaction is... | \\( \bigcirc \\) endothermic. \\( \bigcirc \\) exothermic. |
|---|
| \\( \
\\) | \\( \square \mathrm { kj } \\) |
Step1: Determine the type of reaction
When \(\Delta H<0\), the reaction is exothermic. Here \(\Delta H=- 184\space kJ<0\), so the reaction is exothermic.
Step2: Calculate the moles of \(Cl_{2}\)
The molar mass of \(Cl_{2}\) is \(M = 70.90\space g/mol\). The number of moles \(n=\frac{m}{M}\), where \(m = 71.0\space g\). So \(n=\frac{71.0\space g}{70.90\space g/mol}\approx1.00\space mol\)
Step3: Calculate the heat released
From the reaction \(Cl_{2}(g)+H_{2}(g)\to2HCl(g)\space\Delta H=-184\space kJ\), when \(1\space mol\) of \(Cl_{2}\) reacts, \(184\space kJ\) of heat is released. Since \(n(Cl_{2}) = 1.00\space mol\), the heat released \(q = 184\space kJ\)
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- This reaction is exothermic.
- Yes, released.
- \(184\space kJ\)