Question

this is the chemical formula for zinc bromate:
zn(bro₃)₂.
calculate the mass percent of oxygen in zinc bromate. round your answer to the nearest percentage.
%

Explanation:

Step1: Calculate the molar mass of each element in \(Zn(BrO_3)_2\)

• Molar mass of \(Zn\): \(M_{Zn}=65.38\space g/mol\)
• Molar mass of \(Br\): \(M_{Br} = 79.904\space g/mol\), and there are \(2\) \(Br\) atoms. So total mass of \(Br\) is \(2\times79.904 = 159.808\space g/mol\)
• Molar mass of \(O\): \(M_O=16.00\space g/mol\), and there are \(6\) \(O\) atoms (\(2\times3\)). So total mass of \(O\) is \(6\times16.00=96.00\space g/mol\)

Step2: Calculate the molar mass of \(Zn(BrO_3)_2\)

\(M = 65.38+159.808 + 96.00=321.188\space g/mol\)

Step3: Calculate the mass percent of \(O\)

Mass percent of \(O=\frac{96.00}{321.188}\times100\%\)

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Answer:

\(30\%\)