Question

ch 20* you have an srs of six observations from a normally distributed population. what critical value would you use to obtain an 80% confidence interval for the mean μ of the population? 1.476 1.440 2.015

Explanation:

Step1: Determine the degrees of freedom

The degrees of freedom \(df=n - 1\), where \(n = 6\). So \(df=6-1 = 5\).

Step2: Find the significance level

The confidence level is \(C = 0.80\). The significance level \(\alpha=1 - C=1 - 0.80=0.20\). And \(\frac{\alpha}{2}=\frac{0.20}{2}=0.10\).

Step3: Look up the t - value in the t - distribution table

We look for the row with \(df = 5\) and the column corresponding to the upper - tail probability of \(0.10\) in the t - distribution table. The value is \(t_{\alpha/2}=1.476\).

Answer:

1.476