QUESTION IMAGE
Question
for a certain class, the following data table compares how many students play an instrument or a sport. what is the probability that a student chosen randomly from the class plays neither a sport nor an instrument?
| plays an instrument | does not play an instrument | |
|---|---|---|
| does not play a sport | 10 | 3 |
Step1: Find total number of students
First, we sum up all the values in the table. The values are 5, 4, 10, and 3. So total students $= 5 + 4 + 10 + 3 = 22$.
Step2: Find number of students who play neither
The number of students who play neither a sport nor an instrument is the value in the cell where "Does not play a sport" and "Does not play an instrument" intersect, which is 3.
Step3: Calculate the probability
Probability is the number of favorable outcomes (students who play neither) divided by the total number of students. So probability $= \frac{3}{22}$.
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$\frac{3}{22}$