Question

in 5 - card poker, find the probability of being dealt the following hand. refer to the table. note that a standard deck of playing cards has 52 cards—4 suits (clubs, diamonds, hearts, spades), where each suit has 13 cards (ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king). four of a kind the probability of being dealt four of a kind is (type an integer or decimal rounded to eight decimal places as needed.)

event e	number of outcomes favorable to e
straight flush	36
four of a kind	624
full house	3744
flush	5108
straight	10200
three of a kind	54912
two pairs	123552
one pair	1098240
no pair	1302540
total	2598960

Explanation:

Step1: Recall Probability Formula

Probability \( P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \).

Step2: Identify Values

From the table, number of favorable outcomes for four of a kind is \( 624 \), total outcomes is \( 2598960 \).

Step3: Calculate Probability

\( P = \frac{624}{2598960} \approx 0.0002401 \) (rounded to eight decimal places).

Answer:

\( 0.00024010 \) (or more precisely, \( \frac{624}{2598960} = 0.0002400960384 \approx 0.00024010 \) when rounded to eight decimal places)