Question

at a candy store, the small bag of chocolate holds 8 ounces of chocolate. the large bag holds 50% more than that. how much chocolate does the large bag hold? the unknown value, which represents the large bag of chocolate, is labeled with a question mark on the double number line. write an equation to find the amount of chocolate the large bag holds. double number line: top (chocolate ounces): 0, 8, ?; bottom (percentage): 0%, 50%, 100%, 150% \\(\square \cdot \square = \square\\) options: 150%, ?, 8

Explanation:

Step1: Identify the base amount

The small bag holds 8 ounces, so the base amount is 8.

Step2: Determine the percentage multiplier

The large bag holds 50% more than the small one, so it's 100% + 50% = 150% of the small bag's amount. 150% as a decimal or multiplier is 1.5, but in percentage terms for the equation, we use 150% (or 1.5, but here we use the percentage value as given in the number line).

Step3: Set up the equation

To find the amount in the large bag, we multiply the small bag's amount (8) by the percentage multiplier (150% or 1.5). So the equation is \( 8 \times 150\% =? \) (where? is the amount in the large bag). Filling in the boxes, we have 8, 150%, and the result (which would be 12, but for the equation setup, the boxes are 8, 150%, and the unknown we're solving for, but in the given format, the equation is \( 8 \times 150\% =? \) with the boxes filled as 8, 150%, and the result. But since we just need to write the equation, the first box is 8, the second is 150%, and the third is the amount (which we can calculate as 12, but the equation is \( 8 \times 150\% = 12 \)).

Answer:

The equation is \( \boxed{8} \times \boxed{150\%} = \boxed{12} \) (or in the format of the boxes, the first box is 8, the second is 150%, and the third is 12).