Question

calculate the percent composition of nitrogen in ammonium nitrate (nh₄no₃).

Explanation:

Step1: Calculate molar mass of \(NH_4NO_3\)

Molar mass of \(N = 14\space g/mol\), \(H=1\space g/mol\), \(O = 16\space g/mol\).
\(M(NH_4NO_3)=2\times14 + 4\times1+3\times16\)
\(M(NH_4NO_3)=28 + 4+48=80\space g/mol\)

Step2: Calculate mass of nitrogen in \(NH_4NO_3\)

There are 2 \(N\) atoms in \(NH_4NO_3\). Mass of \(N\) in \(NH_4NO_3\): \(m(N)=2\times14 = 28\space g/mol\)

Step3: Calculate percent composition of \(N\)

Percent composition of \(N=\frac{m(N)}{M(NH_4NO_3)}\times100\%=\frac{28}{80}\times 100\% = 35\%\)

Answer:

35.0%