Question

calculate the molarity of each aqueous solution with the given amount of nacl and final volume. be sure each of your answer entries has the correct number of significant figures.
note: reference the si prefixes table for additional information.
part 1 of 3
3.40 mol nacl in 0.570 l solution
m
part 2 of 3
48.0 g nacl in 6.35 l solution
m
part 3 of 3
84.4 g nacl in 750. ml solution
m

Explanation:

Part 1 of 3

Step1: Recall the formula for molarity

Molarity \( M=\frac{n}{V}\), where \(n\) is the number of moles of solute and \(V\) is the volume of the solution in liters.
Given \(n = 3.40\space mol\) and \(V=0.570\space L\)

Step2: Calculate the molarity

\(M=\frac{3.40\space mol}{0.570\space L}\approx 5.96\space M\)

Part 2 of 3

Step1: Calculate the number of moles of \(NaCl\)

The molar mass of \(NaCl\) is \(M_{NaCl}=58.44\space g/mol\). Using the formula \(n=\frac{m}{M}\), where \(m = 48.0\space g\)
\(n=\frac{48.0\space g}{58.44\space g/mol}\approx 0.821\space mol\)

Step2: Calculate the molarity

Given \(V = 6.35\space L\), using \(M=\frac{n}{V}\)
\(M=\frac{0.821\space mol}{6.35\space L}\approx 0.129\space M\)

Part 3 of 3

Step1: Convert volume to liters

Since \(1\space L=1000\space mL\), \(V = 750.\space mL=0.750\space L\)

Step2: Calculate the number of moles of \(NaCl\)

Using \(n=\frac{m}{M}\) with \(m = 84.4\space g\) and \(M = 58.44\space g/mol\)
\(n=\frac{84.4\space g}{58.44\space g/mol}\approx 1.44\space mol\)

Step3: Calculate the molarity

Using \(M=\frac{n}{V}\)
\(M=\frac{1.44\space mol}{0.750\space L}=1.92\space M\)

Answer:

Part 1 of 3: \(5.96\space M\)
Part 2 of 3: \(0.129\space M\)
Part 3 of 3: \(1.92\space M\)