calculate the mass of 0.25 mol of magnesium oxide. 2 marks

question 2: reacting masses 6 marks

calculate the mr of calcium carbonate, caco3. ar: ca = 40, c = 12, o = 16. 1 mark

Question

calculate the mass of 0.25 mol of magnesium oxide. 2 marks

question 2: reacting masses 6 marks

calculate the mr of calcium carbonate, caco3. ar: ca = 40, c = 12, o = 16. 1 mark

Accepted Answer

{ "quality": "clear", "question_count": 2, "skills_matched": [ "step_cot", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Relative Formula Mass", "Stoichiometric Calculations" ], "new_concepts": [ "Molar Mass Calculation" ], "current_concepts": [ "Relative Formula Mass", "Stoichiometric Calculations", "Molar Mass Calculation" ] } ## Calculate molar mass of magnesium oxide $$ \begin{aligned} &A_r(\text{Mg}) = 24.3\text{ g/mol},\quad A_r(\text{O}) = 16.0\text{ g/mol}\ &M(\text{MgO}) = 24.3 + 16.0 = 40.3\text{ g/mol} \end{aligned} $$ ## Calculate mass of magnesium oxide $$ \begin{aligned} &n = 0.25\text{ mol}\ &m = n \times M = 0.25\text{ mol} \times 40.3\text{ g/mol} = 10.075\text{ g} \approx 10\text{ g} \end{aligned} $$ ## Calculate relative formula mass of calcium carbonate $$ \begin{aligned} &M_r(\text{CaCO}_3) = A_r(\text{Ca}) + A_r(\text{C}) + 3 \times A_r(\text{O})\ &M_r(\text{CaCO}_3) = 40 + 12 + 3 \times 16 = 100 \end{aligned} $$ ## Question 1 $10\text{ g}$ (or $10.1\text{ g}$) ## Question 2 $100$ { "subject": "Natural Science", "question_type": "Multi-part", "knowledge_point": [ "Natural Science", "Chemistry", "Stoichiometric Calculations" ] }

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Calculate molar mass of magnesium oxide

Calculate mass of magnesium oxide

Calculate relative formula mass of calcium carbonate

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Question 1

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