Question

bromine liquid reacts with aqueous potassium iodide to form solid iodine and aqueous potassium bromide. express your answer as a chemical equation including phases. a chemical reaction does not occur for this question.

Explanation:

Step1: Identify reactants and products

Reactants: Br₂ (liquid), KI (aqueous); Products: I₂ (solid), KBr (aqueous)

Step2: Write unbalanced equation

$\text{Br}_2(l) + \text{KI}(aq)
ightarrow \text{I}_2(s) + \text{KBr}(aq)$

Step3: Balance the equation

Balance Br: 2 KBr needed; Balance K: 2 KI needed; Balance I: 1 I₂ formed.
Balanced equation: $\text{Br}_2(l) + 2\text{KI}(aq)
ightarrow \text{I}_2(s) + 2\text{KBr}(aq)$

Answer:

$\text{Br}_2(l) + 2\text{KI}(aq)
ightarrow \text{I}_2(s) + 2\text{KBr}(aq)$