Question

1. _br₂ + _nacl → _na + _br²cl²

Explanation:

Step1: Balance the bromine atoms

On the left - hand side, we have \(Br_2\) (2 bromine atoms). On the right - hand side, in \(Br_2Cl_2\), there are 2 bromine atoms. So the coefficient of \(Br_2\) and \(Br_2Cl_2\) can be 1 for now.

Step2: Balance the chlorine atoms

In \(NaCl\) (1 chlorine atom per formula unit) and \(Br_2Cl_2\) (2 chlorine atoms). To balance chlorine, since we have 2 chlorine atoms in \(Br_2Cl_2\), we set the coefficient of \(NaCl\) to 2.

Step3: Balance the sodium atoms

With a coefficient of 2 for \(NaCl\) (2 sodium atoms), we set the coefficient of \(Na\) to 2.

Answer:

\(1Br_2 + 2NaCl
ightarrow2Na + 1Br_2Cl_2\)