Question

a box contains 30 new phones of which 8 are nokia, 10 are iphones, 12 are samsung. if a phone is drawn at random, find the probability that it is neither a nokia nor an iphone.

Explanation:

Step1: Find the number of non - Nokia and non - iPhone phones

The total number of phones is 30. The number of Nokia phones is 8 and the number of iPhone phones is 10. So the number of phones that are neither Nokia nor iPhone is the number of Samsung phones, which is 12.

Step2: Calculate the probability

The probability of an event is the number of favorable outcomes divided by the total number of outcomes. Here, the number of favorable outcomes (neither Nokia nor iPhone) is 12, and the total number of outcomes is 30. So the probability $P=\frac{12}{30}=\frac{2}{5}$.

Answer:

$\frac{2}{5}$ (corresponding to the option with $\frac{2}{5}$)