Question

a bottling company marks a 0 for every bottle that comes out correct and a 1 for every defective bottle. estimate the probability that the next bottle is defective.
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0
(1 point)
\\(\frac{19}{20}\\)
\\(\frac{1}{20}\\)
\\(\frac{18}{20}\\)
\\(\frac{0}{20}\\)

Explanation:

Step1: Count total number of bottles

Count the number of digits in \(00000000000000100000\). There are \(n = 20\) digits.

Step2: Count number of defective bottles

Count the number of \(1\)s. There is \(m=1\) one.

Step3: Calculate probability

The probability \(P\) of an event is \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, \(P = \frac{m}{n}\). Substituting \(m = 1\) and \(n=20\), we get \(P=\frac{1}{20}\).

Answer:

\(\frac{1}{20}\)