Question

beryllium and iodine
express your answer as a chemical formula.
a chemical reaction does not occur for this question.

Explanation:

Step1: Determine the charges of ions

Beryllium (\(Be\)) is in group 2 of the periodic table, so it forms \(Be^{2 +}\) ions. Iodine (\(I\)) is in group 17, so it forms \(I^{-}\) ions.

Step2: Use the criss - cross method

To form a neutral compound, the charges must balance. For \(Be^{2+}\) and \(I^{-}\), we need 1 \(Be^{2+}\) and 2 \(I^{-}\) ions.

Answer:

\(BeI_{2}\)