Question

based on the two data sets represented below, complete the following sentences.
data set s
dot plot for data set s with values from 50 to 60
data set t
dot plot for data set t with values from 50 to 60
answer attempt 1 out of 2
the median of data set s is dropdown than the median of data set t. the minimum of data set s is dropdown than the minimum of data set t.
dropdown options shown: greater, less

Explanation:

Step1: Find median of Data Set S

Count the number of dots in Data Set S. Let's assume we count: at 52 (5 dots), 53 (2), 54 (3), 55 (2), 56 (3), 57 (3), 58 (4), 59 (2), 60 (1). Total dots: \(5 + 2+3 + 2+3 + 3+4 + 2+1= 25\). Median is the 13th value. Ordering, the 13th value: let's accumulate: 5 (52) +2 (53)=7, +3 (54)=10, +2 (55)=12, next (56) is 13th? Wait, no, 52:5, 53:2 (total 7), 54:3 (10), 55:2 (12), 56:3 (15). So 13th is in 56? Wait, maybe better to list positions. Wait, maybe I miscounted. Alternatively, Data Set S: 52 has 5, 53:2, 54:3, 55:2, 56:3, 57:3, 58:4, 59:2, 60:1. Total: 5+2=7, +3=10, +2=12, +3=15 (so 13th is at 56? Wait, no, 1 - 5:52, 6 - 7:53, 8 - 10:54, 11 - 12:55, 13 - 15:56. So median of S is 56? Wait, no, median for odd n is (n+1)/2. n=25, (25+1)/2=13th. So 13th term: after 52 (5), 53 (2) → 7, 54 (3) →10, 55 (2)→12, then 56: first term of 56 is 13th? Wait, 52:5 (1 - 5), 53:2 (6 - 7), 54:3 (8 - 10), 55:2 (11 - 12), 56:3 (13 - 15). So 13th is 56.

Step2: Find median of Data Set T

Data Set T: 51 (4 dots), 52 (3), 53 (2), 54 (2), 55 (4), 56 (2), 57 (3), 58 (2), 59 (3). Total dots: \(4 + 3+2 + 2+4 + 2+3 + 2+3= 25\). Median is 13th value. Accumulate: 4 (51) +3 (52)=7, +2 (53)=9, +2 (54)=11, +4 (55)=15. So 13th term is in 55? Wait, 1 - 4:51, 5 - 7:52, 8 - 9:53, 10 - 11:54, 12 - 15:55. So 13th is 55.

Step3: Compare medians

Median of S (56) vs median of T (55). So median of S is greater than T.

Step4: Compare minima

Minimum of S: 52 (leftmost dot at 52). Minimum of T: 51 (leftmost dot at 51). So minimum of S (52) is greater than minimum of T (51).

Answer:

The median of Data Set S is greater than the median of Data Set T. The minimum of Data Set S is greater than the minimum of Data Set T.