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Question
based on the periodic table shown, elements from columns b and e will combine in which ratio to form an ionic compound?
Step1: Determine the charge of elements in column B
Elements in column B (Group 1 of the periodic table) lose 1 electron to form \(+1\) ions.
Step2: Determine the charge of elements in column E
Elements in column E (Group 6 of the periodic table) gain 2 electrons to form \(-2\) ions.
Step3: Use charge balance for ionic compound
To form a neutral ionic compound, let the number of \(B\) ions be \(x\) and \(E\) ions be \(y\). Using charge balance \( (+1)x+(-2)y = 0\). Solving for \(\frac{x}{y}\), we get \(x = 2y\) or \(\frac{x}{y}=\frac{2}{1}\).
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The ratio of elements from column \(B\) to column \(E\) is \(2:1\).