Question

based on the following balanced equation: c₃h₈ + 5o₂ → 3co₂ + 4h₂o what is the ratio of propane to water? 1c₃h₈:4h₂o 3co₂:5o₂ 1c₃h₈:5o₂

Explanation:

Step1: Identify reactants and products

The balanced equation is $C_3H_8 + 5O_2
ightarrow3CO_2 + 4H_2O$. Propane is $C_3H_8$ and water is $H_2O$.

Step2: Determine the ratio

The coefficient of propane ($C_3H_8$) is 1 and the coefficient of water ($H_2O$) is 4. So the ratio of propane to water is $1C_3H_8:4H_2O$.

Answer:

$1C_3H_8:4H_2O$