Question

based on the equation, how many grams of \\(\text{br}_2\\) are required to react completely with 36.2 grams of \\(\text{alcl}_3\\)?

\\2\text{alcl}_3 + 3\text{br}_2 \
ightarrow 2\text{albr}_3 + 3\text{cl}_2\\

• 65.2 grams
• 69.8 grams
• 72.1 grams
• 76.5 grams

Explanation:

Calculate molar masses of reactants

$$
LATEXBLOCK0
$$

Convert mass of aluminum chloride to moles

$$ n(\text{AlCl}_3) = \frac{36.2\text{ g}}{133.33\text{ g/mol}} \approx 0.2715\text{ mol} $$

Determine required mass of bromine using stoichiometry

$$
LATEXBLOCK1
$$

Answer:

• (A) 65.2 grams (Correct answer)
• (B) 69.8 grams
• (C) 72.1 grams
• (D) 76.5 grams