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Question
based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation: (\\(\boldsymbol{\vee}\\))bao₂ + (\\(\boldsymbol{\vee}\\))h₂so₄ → (\\(\boldsymbol{\vee}\\))h₂o₂ + (\\(\boldsymbol{\vee}\\))baso₄
Step1: Analyze Ba atoms
On the left, we have \( \text{BaO}_2 \), so 1 Ba atom. On the right, \( \text{BaSO}_4 \) has 1 Ba atom. So Ba is balanced initially, so coefficient for \( \text{BaO}_2 \) and \( \text{BaSO}_4 \) could be 1.
Step2: Analyze S atoms
Left: \( \text{H}_2\text{SO}_4 \) has 1 S. Right: \( \text{BaSO}_4 \) has 1 S. So S is balanced if \( \text{H}_2\text{SO}_4 \) and \( \text{BaSO}_4 \) have coefficient 1.
Step3: Analyze H atoms
Left: \( \text{H}_2\text{SO}_4 \) has 2 H. Right: \( \text{H}_2\text{O}_2 \) has 2 H. So H is balanced if \( \text{H}_2\text{SO}_4 \) and \( \text{H}_2\text{O}_2 \) have coefficient 1.
Step4: Analyze O atoms
Left: \( \text{BaO}_2 \) (2 O) + \( \text{H}_2\text{SO}_4 \) (4 O) = 6 O. Right: \( \text{H}_2\text{O}_2 \) (2 O) + \( \text{BaSO}_4 \) (4 O) = 6 O. So O is balanced.
So coefficients are 1, 1, 1, 1.
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1 (for \( \text{BaO}_2 \)), 1 (for \( \text{H}_2\text{SO}_4 \)), 1 (for \( \text{H}_2\text{O}_2 \)), 1 (for \( \text{BaSO}_4 \))