Question

a baseball player hit 63 home runs in a season. of the 63 home runs, 22 went to right field, 17 went to right center field, 12 went to center field, 11 went to left center field, and 1 went to left field. (a) what is the probability that a randomly selected home run was hit to right field? (b) what is the probability that a randomly selected home run was hit to left field? (c) was it unusual for this player to hit a home run to left field? explain. (a) the probability that a randomly selected home run was hit to right field is (round to three decimal places as needed.)

Explanation:

Step1: Calculate the probability formula

The probability formula is \(P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, the total number of home - runs \(n = 63\), and the number of home - runs to right field \(m=22\).

Step2: Substitute values into the formula

Substitute \(m = 22\) and \(n = 63\) into the formula \(P=\frac{22}{63}\).

$$P=\frac{22}{63}\approx0.349$$

Answer:

\(0.349\)