Question

a baseball player hit 63 home runs in a season. of the 63 home runs, 22 went to right field, 17 went to right center field, 12 went to center field, 11 went to left center field, and 1 went to left field. (a) what is the probability that a randomly selected home run was hit to right field? (b) what is the probability that a randomly selected home run was hit to left field? (c) was it unusual for this player to hit a home run to left field? explain. (a) the probability that a randomly selected home run was hit to right field is 0.349 (round to three decimal places as needed.) (b) the probability that a randomly selected home run was hit to left field is (round to three decimal places as needed.)

Explanation:

Step1: Use the probability formula

The probability formula is \(P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\).
For part (b), the number of favorable outcomes (home - runs to left field) is \(n = 1\), and the total number of outcomes (total home - runs) is \(N=63\).

Step2: Calculate the probability

Substitute the values into the formula: \(P=\frac{1}{63}\).
Using a calculator, \(\frac{1}{63}\approx0.016\) (rounded to three decimal places).

Answer:

(a) The probability that a randomly selected home run was hit to right field is \(0.349\).
(b) The probability that a randomly selected home run was hit to left field is \(0.016\).