Question

a balloon tied to the ground with a rope floats in the air. the volume of the balloon is 1 l and the pressure in the balloon is 0.8 atm. if the balloon is placed deep underwater where it compresses so the pressure in the balloon is 4 atm, what will be the new volume of the balloon?
do not include units in your answer.

Explanation:

Step1: Recall Boyle's Law

Boyle's Law states \(P_1V_1 = P_2V_2\), where \(P_1 = 0.8\), \(V_1 = 1\), \(P_2 = 4\), and \(V_2\) is the unknown.

Step2: Solve for \(V_2\)

Rearrange the formula to \(V_2=\frac{P_1V_1}{P_2}\). Substitute the values: \(V_2=\frac{0.8\times1}{4}\).

Step3: Calculate the value

\(V_2 = 0.2\)

Answer:

\(0.2\)