balancing equation mixed review
7. rxn type: ___ + ___ → ___ therefore its: syn, sr, dr, dec, com
___ cao + ___ h₂o → ___ ca(oh)₂
ca ca
o o
h h
8. rxn type: ___ + ___ → ___ + ___ therefore its: syn, sr, dr, dec, com
____ naf + ____ br₂ → ____ nabr + ____ f₂
na na
f f
br br
9. rxn type: ___ + ___ → ___ + ___ therefore its: syn, sr, dr, dec, com
____ al + ___ 6 ___ hcl → ____ h₂ + ____ alcl₃
al al
h h
cl cl
10. rxn type: ___ + ___ → ___ + ___ therefore its: syn, sr, dr, dec, com
____ cu + ____ o₂ → ____ cu₂o
cu cu
o o

Question

Accepted Answer

# Explanation:
## Step1: Balance the equation $CaO + H_2O \to Ca(OH)_2$
Count the number of each atom on both sides. For $Ca$: 1 on left and 1 on right. For $O$: 1 + 1 = 2 on left and 2 on right. For $H$: 2 on left and 2 on right. So the coefficients are $1\ CaO+1\ H_2O \to 1\ Ca(OH)_2$. The reaction type is $A + B\to AB$ (two reactants combine to form one product), so it's a synthesis reaction (Syn).
## Step2: Balance the equation $NaF+Br_2\to NaBr + F_2$
Use the method of trial - and - error. For $Na$: assume the coefficient of $NaF$ is $2$, then the coefficient of $NaBr$ is $2$. For $Br$: since the coefficient of $NaBr$ is $2$, the coefficient of $Br_2$ is $1$. For $F$:  with the coefficient of $NaF$ as $2$, the coefficient of $F_2$ is $1$. The balanced equation is $2NaF + 1Br_2\to2NaBr+1F_2$. The reaction type is $AB + C\to AC + B$ (a single element replaces another in a compound), so it's a single - replacement reaction (SR).
## Step3: Balance the equation $Al+HCl\to H_2+AlCl_3$
Given $HCl$ coefficient is $6$. For $Cl$: in $AlCl_3$, since there are $6\ Cl$ atoms from $6HCl$, the coefficient of $AlCl_3$ is $2$. For $Al$: the coefficient of $Al$ is $2$. For $H$: $6\ H$ atoms from $6HCl$ give a coefficient of $3$ for $H_2$. The balanced equation is $2Al + 6HCl\to3H_2+2AlCl_3$. The reaction type is $AB + C\to AC + B$ (a single element replaces another in a compound), so it's a single - replacement reaction (SR).
## Step4: Balance the equation $Cu+O_2\to Cu_2O$
Use the least - common - multiple method. For $O$: LCM of $2$ (from $O_2$) and $1$ (from $Cu_2O$) is $2$. So the coefficient of $Cu_2O$ is $2$. For $Cu$: since the coefficient of $Cu_2O$ is $2$, the coefficient of $Cu$ is $4$. The balanced equation is $4Cu+1O_2\to2Cu_2O$. The reaction type is $A + B\to AB$ (two reactants combine to form one product), so it's a synthesis reaction (Syn).

# Answer:
7. $1\ CaO+1\ H_2O \to 1\ Ca(OH)_2$, Syn
8. $2NaF + 1Br_2\to2NaBr+1F_2$, SR
9. $2Al + 6HCl\to3H_2+2AlCl_3$, SR
10. $4Cu+1O_2\to2Cu_2O$, Syn

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QUESTION IMAGE

Question

Explanation:

Step1: Balance the equation \(CaO + H_2O \to Ca(OH)_2\)

Step2: Balance the equation \(NaF+Br_2\to NaBr + F_2\)

Step3: Balance the equation \(Al+HCl\to H_2+AlCl_3\)

Step4: Balance the equation \(Cu+O_2\to Cu_2O\)

Answer: