QUESTION IMAGE
Question
balancing chemical equations
checking comprehension
balance the following equations:
- ( p + o _ { 2 }
ightarrow p _ { 2 } o _ { 5 } )
- ( agno _ { 3 } + cacl _ { 2 }
ightarrow agcl + ca ( no _ { 3 } ) _ { 2 } )
- ( na + o _ { 2 }
ightarrow na _ { 2 } o )
- ( h _ { 3 } po _ { 4 } + koh
ightarrow k _ { 3 } po _ { 4 } + h _ { 2 } o )
- ( al _ { 2 } o _ { 3 } + al + o _ { 2 } )
- ( fe + cl _ { 2 }
ightarrow fecl _ { 3 } )
multiple-choice question
( square 4 p + 5 o _ { 2 }
ightarrow 1 p _ { 4 } o _ { 10 } )
( square 1 p + 1 o _ { 2 }
ightarrow 1 p _ { 4 } o _ { 10 } )
( square 2 p + 2 o _ { 2 }
ightarrow 2 p _ { 4 } o _ { 10 } )
Step1: Count atoms on both sides
On the left - hand side (LHS), we have \(P\) and \(O_2\). On the right - hand side (RHS), we have \(P_4O_{10}\).
For \(P\) atoms: In \(P_4O_{10}\), the number of \(P\) atoms is \(4\). So we need \(4\) \(P\) atoms on the LHS.
For \(O\) atoms: In \(P_4O_{10}\), the number of \(O\) atoms is \(10\). Since \(O_2\) is on the LHS, and if we let the coefficient of \(O_2\) be \(x\), then \(2x = 10\), so \(x = 5\).
Step2: Write the balanced equation
The balanced equation is \(4P+5O_2
ightarrow P_4O_{10}\)
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\(4P + 5O_2
ightarrow P_4O_{10}\) (the first option among the multiple - choice)