Question

b. balanced formula equation:
hno₂(aq) + koh(aq)
→+
complete ionic equation:
++
→++
net ionic equation:
+
→+
c. balanced formula equation:
ba(oh)₂(aq) + hbr(aq)
→+
complete ionic equation:
+++
→++
net ionic equation:
+→

Explanation:

Step1: Balance formula equation for \(HNO_{2}(aq)+KOH(aq)\)

Acid - base reaction: \(HNO_{2}(aq)+KOH(aq)
ightarrow KNO_{2}(aq)+H_{2}O(l)\)
Coefficients are \(1\) for each reactant and product.

Step2: Write complete ionic equation

\(HNO_{2}\) is a weak acid (\(HNO_{2}(aq)\)), \(KOH\) dissociates (\(K^{+}(aq)+OH^{-}(aq)\)), \(KNO_{2}\) dissociates (\(K^{+}(aq)+NO_{2}^{-}(aq)\)), \(H_{2}O\) is molecular.
\(HNO_{2}(aq)+K^{+}(aq)+OH^{-}(aq)
ightarrow K^{+}(aq)+NO_{2}^{-}(aq)+H_{2}O(l)\)

Step3: Write net ionic equation

Cancel out spectator ion \(K^{+}\)
\(HNO_{2}(aq)+OH^{-}(aq)
ightarrow NO_{2}^{-}(aq)+H_{2}O(l)\)

Step4: Balance formula equation for \(Ba(OH)_{2}(aq)+HBr(aq)\)

\(Ba(OH)_{2}(aq)+2HBr(aq)
ightarrow BaBr_{2}(aq)+2H_{2}O(l)\)

Step5: Write complete ionic equation

\(Ba^{2 +}(aq)+2OH^{-}(aq)+2H^{+}(aq)+2Br^{-}(aq)
ightarrow Ba^{2+}(aq)+2Br^{-}(aq)+2H_{2}O(l)\)

Step6: Write net ionic equation

Cancel out spectator ions \(Ba^{2+}\) and \(Br^{-}\)
\(H^{+}(aq)+OH^{-}(aq)
ightarrow H_{2}O(l)\)

Answer:

b.

• Balanced formula equation: \(HNO_{2}(aq)+KOH(aq)

ightarrow KNO_{2}(aq)+H_{2}O(l)\)

• Complete ionic equation: \(HNO_{2}(aq)+K^{+}(aq)+OH^{-}(aq)

ightarrow K^{+}(aq)+NO_{2}^{-}(aq)+H_{2}O(l)\)

• Net ionic equation: \(HNO_{2}(aq)+OH^{-}(aq)

ightarrow NO_{2}^{-}(aq)+H_{2}O(l)\)

c.

• Balanced formula equation: \(Ba(OH)_{2}(aq)+2HBr(aq)

ightarrow BaBr_{2}(aq)+2H_{2}O(l)\)

• Complete ionic equation: \(Ba^{2 +}(aq)+2OH^{-}(aq)+2H^{+}(aq)+2Br^{-}(aq)

ightarrow Ba^{2+}(aq)+2Br^{-}(aq)+2H_{2}O(l)\)

• Net ionic equation: \(H^{+}(aq)+OH^{-}(aq)

ightarrow H_{2}O(l)\)