Question

balance the reaction, do not leave any fractions, dont leave anything blank, then answer the questions about the reaction
1 hno₃ + 2 al → 3 h₂(g) + 4 al(no₃)₃
this is an 5 reaction.
is this a redox reaction? (yes/no)6, because al⁰ is oxidized to al⁺³, and because h⁺¹ is 7 to h₂⁰.
will the reaction happen as it is written? (yes/no)8, because h₂ is a gas and will leave the reaction container. the reverse reaction would not happen.
a. 1 b. 2 c. 3 d. 4 e. 5 f. 6 g. 7 h. 8 i. 9
j. 10 k. 12 l. 14 m. 16 n. 18 o. 20 p. 22 q. 24 r. 26
s. 28 t. synthesis u. decomposition v. single displacement
w. double displacement x. neutralization y. yes z. no aa. reactive
bb. stable cc. oxidized dd. reduced

Explanation:

Step1: Balance the chemical equation

For the given reaction \( \text{HNO}_3+\text{Al}\to\text{H}_2+\text{Al(NO}_3)_3\), balance the nitrate ions (\(\text{NO}_3^-\)). Let's assume the coefficient of \(\text{Al(NO}_3)_3\) is \(x\). Then the coefficient of \(\text{HNO}_3\) should be \(3x\) (because of the nitrate ions). For hydrogen atoms, if the coefficient of \(\text{HNO}_3\) is \(3x\), and the coefficient of \(\text{H}_2\) is \(y\), then \(3x = 2y\). For aluminum atoms, if the coefficient of \(\text{Al(NO}_3)_3\) is \(x\), the coefficient of \(\text{Al}\) is \(x\).

Let \(x = 2\), then the coefficient of \(\text{HNO}_3\) is \(6\) (since \(3x=6\)), the coefficient of \(\text{Al}\) is \(2\), the coefficient of \(\text{H}_2\) is \(3\) (since \(y = 3\) from \(3x=2y\) when \(x = 2\)), and the coefficient of \(\text{Al(NO}_3)_3\) is \(2\).

The balanced equation is \(6\text{HNO}_3 + 2\text{Al}\to3\text{H}_2+2\text{Al(NO}_3)_3\)

Step2: Identify the type of reaction

In a single - displacement reaction, an element reacts with a compound and displaces another element from the compound. Here, \(Al\) (an element) reacts with \(\text{HNO}_3\) (a compound) and displaces \(H\) (as \(H_2\)). So, it is a single - displacement reaction (\(V\)).

Step3: Determine if it is a redox reaction

In a redox reaction, there is a change in oxidation states. For \(Al\): \(Al^0\to Al^{3 +}\) (oxidation, loss of electrons). For \(H\): \(H^+\to H_0\) (reduction, gain of electrons). So, it is a redox reaction (\(Y\)). The \(H^+\) is reduced (\(DD\)) to \(H_2\) (since it gains electrons to change its oxidation state from \(+ 1\) to \(0\))

Step4: Determine if the reaction will occur as written

According to the activity series, aluminum is more reactive than hydrogen. So, the reaction \(6\text{HNO}_3 + 2\text{Al}\to3\text{H}_2+2\text{Al(NO}_3)_3\) will occur as written (\(Y\)) because \(Al\) can displace \(H\) from \(HNO_3\) and \(H_2\) (a gas) leaves the reaction mixture, driving the reaction forward.

Answer:

1. \(6\)
2. \(2\)
3. \(3\)
4. \(2\)
5. \(V\) (single displacement)
6. \(Y\) (yes)
7. \(DD\) (reduced)
8. \(Y\) (yes)