Question

1. balance the equation for propane (c₃h₈) is burned. by dragging coefficients.

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1 c₃h₈ + 5 o₂ → 3 co₂ + 4 h₂o
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1. refer to the balanced equation in the previous problem.

how many oxygen atoms are on each side of the balanced equation?
atoms
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Explanation:

Step1: Identify the balanced equation

The balanced equation from problem 9 is \( \ce{C3H8 + 5O2 -> 3CO2 + 4H2O} \).

Step2: Calculate oxygen atoms on the left side

For \( \ce{O2} \) with coefficient 5, each \( \ce{O2} \) has 2 oxygen atoms. So total oxygen atoms on the left: \( 5\times2 = 10 \).

Step3: Calculate oxygen atoms on the right side

• For \( \ce{CO2} \) with coefficient 3: each \( \ce{CO2} \) has 2 oxygen atoms, so \( 3\times2 = 6 \).
• For \( \ce{H2O} \) with coefficient 4: each \( \ce{H2O} \) has 1 oxygen atom, so \( 4\times1 = 4 \).
• Total on the right: \( 6 + 4 = 10 \).

Answer:

10