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balance the equation ag₂o → ag + o₂

Question

balance the equation
ag₂o → ag + o₂

Explanation:

Step1: Balance oxygen atoms

On the left - hand side, we have \(1\) oxygen atom in \(Ag_2O\), and on the right - hand side, we have \(2\) oxygen atoms in \(O_2\). To balance the oxygen atoms, we can use the least - common multiple of \(1\) and \(2\) (which is \(2\)). So, we put a coefficient of \(2\) in front of \(Ag_2O\) and a coefficient of \(1\) in front of \(O_2\). The equation becomes \(2Ag_2O
ightarrow Ag + O_2\).

Step2: Balance silver atoms

After balancing oxygen, we now balance silver atoms. Since we have \(2\times2 = 4\) silver atoms on the left - hand side (\(2Ag_2O\)), we need to put a coefficient of \(4\) in front of \(Ag\) on the right - hand side.

Answer:

The balanced equation is \(2Ag_2O
ightarrow4Ag + O_2\), so the coefficients are \(2\), \(4\), \(1\) respectively.