Question

balance the equation s₈ + o₂ → so₃

Explanation:

Step1: Balance sulfur atoms

There are 8 sulfur atoms in \(S_8\). So, the coefficient of \(SO_3\) should be 8 to balance sulfur.
\(S_8+O_2
ightarrow8SO_3\)

Step2: Balance oxygen atoms

On the right - hand side, there are \(8\times3 = 24\) oxygen atoms in \(8SO_3\). So, the coefficient of \(O_2\) should be 12 (\(\frac{24}{2}\)) to balance oxygen.
\(S_8 + 12O_2
ightarrow8SO_3\)

Answer:

The balanced equation is \(S_8+12O_2 = 8SO_3\), so the coefficients are \(1\) (for \(S_8\), already given as \(1\) implicitly in the problem's initial setup), \(12\) (for \(O_2\)), and \(8\) (for \(SO_3\)).