Question

average attendè
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choose the correct answer from each drop - down menu and complete the sentences.
the solution is -- choose the correct answer -- . after -- choose the correct answer -- years, both schools have an average attendance of
-- choose the correct answer -- students.

Explanation:

To solve this, we analyze the graph (though specific drop - down options aren't shown, we can infer from the intersection of the two lines). The solution here refers to the point where the two lines (representing average attendance of two schools) intersect.

Step 1: Find the intersection point

Looking at the graph, we identify the \(x\) - value (years) and \(y\) - value (average attendance) where the two lines meet. From the grid, we can see that the intersection occurs at \(x = 12\) years (by looking at the horizontal axis) and the corresponding \(y\) - value (average attendance) is around 850 (or the value at the intersection point on the vertical axis). The "solution" in the context of a system of linear equations (representing the two attendance lines) is the point of intersection of the two lines.

Step 2: Fill in the blanks

The first blank (the solution) is the point of intersection of the two lines (the ordered pair \((12, 850)\) or the description of the intersection). The second blank is the number of years, which is 12, and the third blank is the average attendance, which is 850 (or the value at the intersection).

Assuming the drop - down options are related to the intersection point:

• The solution is the point where the two lines intersect.
• After 12 years, both schools have an average attendance of 850 (or the relevant value from the graph's intersection) students.

If we consider the standard form of such a problem (finding the intersection of two linear models for school attendance):

Let the two lines be \(y_1\) (for one school) and \(y_2\) (for the other school). The solution to the system \(

$$\begin{cases}y = y_1\\y = y_2\end{cases}$$

\) is the point \((x,y)\) where they cross. From the graph, when \(x = 12\), \(y\) (average attendance) is, say, 850 (depending on the graph's scale).

Answer:

The solution is the point of intersection of the two lines. After 12 years, both schools have an average attendance of 850 students. (The exact numbers may vary slightly depending on the precise graph details, but the key is the intersection point at \(x = 12\) and the corresponding \(y\) - value for average attendance.)