the average adult human burns $2.00 imes10^{3}$ kcal per day in energy. what is this rate in kj per hour?
$2.00 imes10^{3}\frac{kcal}{days} imes(\frac{4.184kj}{1kcal}) imes(\frac{}{})$

Question

the average adult human burns $2.00	imes10^{3}$ kcal per day in energy. what is this rate in kj per hour?
$2.00	imes10^{3}\frac{kcal}{days}	imes(\frac{4.184kj}{1kcal})	imes(\frac{}{})$

Accepted Answer

# Explanation:
## Step1: Convert days to hours
We know that $1$ day has $24$ hours. So the conversion factor is $\frac{1\ \text{day}}{24\ \text{hours}}$

## Step2: Calculate the rate
$$
\begin{align*}
\frac{2.00\times 10^{3}\ \text{kcal}}{\text{day}}\times\frac{4.184\ \text{kJ}}{1\ \text{kcal}}\times\frac{1\ \text{day}}{24\ \text{hours}}&=\frac{2.00\times 10^{3}\times4.184}{24}\ \frac{\text{kJ}}{\text{hour}}\
&=\frac{8368}{24}\ \frac{\text{kJ}}{\text{hour}}\
& = 349\ \frac{\text{kJ}}{\text{hour}}
\end{align*}
$$

# Answer:
$349$

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QUESTION IMAGE

Question

Explanation:

Step1: Convert days to hours

Step2: Calculate the rate

Answer: