Question

avacado oil is a cooking ingredient. the density of avacado oil is 1.16 grams per cubic centimeter. an avacado farmer wants to sell bottles that contain 578 grams of oil. what is the volume of the smallest container that holds 578 grams of oil?
670.5 cm³
498.3 cm³
470.4 cm³
500 cm³

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. We need to solve for $V$, so $V = \frac{m}{
ho}$.

Step2: Substitute values

Given that $m = 578$ grams and $
ho=1.16$ grams per cubic - centimeter. Then $V=\frac{578}{1.16}$.

Step3: Calculate the volume

$V=\frac{578}{1.16}=498.275862\approx498.3\ cm^{3}$.

Answer:

$498.3\ cm^{3}$