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assume that each circle shown below represents one unit. express the sh…

Question

assume that each circle shown below represents one unit. express the shaded amount as an improper fraction and as a mixed number.

answer attempt 1 out of 2
fraction:

mixed number:

Explanation:

Step1: Analyze the circles

Each circle is divided into 10 equal parts. The first circle is fully shaded (10/10), and the second circle has 6 shaded parts (6/10).

Step2: Calculate total shaded as improper fraction

Total shaded parts: \(10 + 6 = 16\), so improper fraction is \(\frac{16}{10}\) (simplify to \(\frac{8}{5}\) if needed, but original division is 10 parts, so initially \(\frac{16}{10}\) or reduced \(\frac{8}{5}\)). Wait, wait, first circle is 10/10 (1 whole), second circle: total parts 10, shaded 6. So total shaded is \(1 + \frac{6}{10}\) as mixed, or \(\frac{10 + 6}{10}=\frac{16}{10}=\frac{8}{5}\) (simplified) or \(\frac{16}{10}\) (original). Wait, maybe the circles are divided into 10? Wait the first circle has 10 shaded, second: let's count. First circle: 10 segments, all shaded. Second circle: 10 segments, 6 shaded (since 4 are white). So total shaded: 10 + 6 = 16, over 10. So improper fraction: \(\frac{16}{10}\) (or simplify to \(\frac{8}{5}\)). Mixed number: \(1\frac{6}{10}\) (or \(1\frac{3}{5}\)). Wait, maybe the denominator is 10? Let's check again.

Wait, first circle: 10 equal parts, all shaded (1 unit). Second circle: 10 equal parts, 6 shaded. So total shaded: 1 (from first) + 6/10 (from second) = 16/10 (improper) or 1 6/10 (mixed). Simplifying: 16/10 = 8/5, 1 6/10 = 1 3/5. But maybe the problem uses denominator 10. Let's confirm.

So step1: each circle is 1 unit, divided into 10 parts. First circle: 10/10 shaded. Second circle: 6/10 shaded. Total shaded: 10/10 + 6/10 = 16/10 (improper fraction). Mixed number: 1 (from 10/10) + 6/10 = 1 6/10.

Step3: Write improper and mixed

Improper fraction: \(\frac{16}{10}\) (or \(\frac{8}{5}\) if simplified). Mixed number: \(1\frac{6}{10}\) (or \(1\frac{3}{5}\)). But let's see the original division. The circles have 10 parts each. So first circle: 10/10, second: 6/10. So total: 16/10 (improper) and 1 6/10 (mixed).

Wait, maybe I miscounted. Let's look at the second circle: how many white? 4. So shaded: 10 - 4 = 6. So yes, 6. So improper fraction: (10 + 6)/10 = 16/10 = 8/5 (simplified). Mixed number: 1 + 6/10 = 1 3/5 (simplified) or 1 6/10.

So the answer:

Improper fraction: \(\frac{16}{10}\) (or \(\frac{8}{5}\))

Mixed number: \(1\frac{6}{10}\) (or \(1\frac{3}{5}\))

But let's check the problem again. The question says "each circle shown below represents one unit. Express the shaded amount as an improper fraction and as a mixed number."

So first circle: 1 unit (10/10). Second circle: 6/10 shaded. So total shaded: 1 + 6/10 = 16/10 (improper) or 1 6/10 (mixed). Simplifying 16/10 to 8/5 and 6/10 to 3/5, so 1 3/5.

So:

Fraction (improper): \(\frac{16}{10}\) (or \(\frac{8}{5}\))

Mixed Number: \(1\frac{6}{10}\) (or \(1\frac{3}{5}\))

But maybe the circles are divided into 10, so initial is 16/10 and 1 6/10.

Answer:

Fraction: \(\frac{16}{10}\) (or \(\frac{8}{5}\))
Mixed Number: \(1\frac{6}{10}\) (or \(1\frac{3}{5}\))

(Note: If simplifying, \(\frac{8}{5}\) and \(1\frac{3}{5}\) are simplified forms. If keeping original denominator, \(\frac{16}{10}\) and \(1\frac{6}{10}\).)