QUESTION IMAGE
Question
ammonium bisulfide
\\(\text{nh}_3(g) + \text{h}_2\text{s}(g) \
ightleftharpoons \text{nh}_4\text{hs}(s)\\)
\\(k = 400.\text{ @ } 35.0\text{ }^\circ\text{c}\\) \\(\delta h_{\text{rxn}} = -83.4\text{ kj}\\)
how does the concentration of \\(\text{nh}_3\\) change when the equilibrium is disturbed as described?
there is not enough information to determine the change in \\(\text{nh}_3\\) concentration.
the \\(\text{nh}_3\\) concentration decreases.
the \\(\text{nh}_3\\) concentration remains unchanged.
the \\(\text{nh}_3\\) concentration increases.
Identify the equilibrium system
Using the Chemical Equilibrium knowledge point
Analyze the disturbance
Using the Le Chateliers Principle knowledge point
- The reaction is exothermic (\(\Delta H < 0\)).
- The question asks how the concentration of \(\mathrm{NH_3}\) changes when the equilibrium is disturbed.
- Although the specific disturbance is cut off in the left-hand text, we can analyze standard disturbances. However, looking closely at the faded text on the left: "Ammonium Bisulfide... is added to...".
- If solid \(\mathrm{NH_4HS}(s)\) is added to the container, we must consider its effect on the heterogeneous equilibrium.
Evaluate the effect of adding solid
Using the Chemical Equilibrium knowledge point
- The equilibrium constant expression for this heterogeneous reaction is:
- Pure solids do not appear in the equilibrium expression because their activity/concentration remains constant.
- Adding or removing pure solid \(\mathrm{NH_4HS}\) does not change the concentrations of the gaseous species, provided some solid is already present to maintain equilibrium.
- Therefore, the concentration of \(\mathrm{NH_3}\) remains unchanged.
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- There is not enough information to determine the change in \(\text{NH}_3\) concentration.
- The \(\text{NH}_3\) concentration decreases.
- The \(\text{NH}_3\) concentration remains unchanged. (Correct answer)
- The \(\text{NH}_3\) concentration increases.