Question

ammonia and oxygen react to form nitrogen monoxide and water, like this:
4nh₃(g) + 5o₂(g) → 4no(g) + 6h₂o(g)
also, a chemist finds that at a certain temperature the equilibrium mixture of ammonia, oxygen, nitrogen monoxide, and water has the following composition:
calculate the value of the equilibrium constant kₚ for this reaction. round your answer to 2 significant digits.
kₚ =

Explanation:

Step1: Write the formula for \(K_p\)

For the reaction \(4NH_3(g)+5O_2(g)\to4NO(g) + 6H_2O(g)\), the formula for \(K_p\) is \(K_p=\frac{P_{NO}^4\times P_{H_2O}^6}{P_{NH_3}^4\times P_{O_2}^5}\)

Step2: Substitute the given values

Substitute \(P_{NH_3} = 17.5\) atm, \(P_{O_2}=60.2\) atm, \(P_{NO}=14.2\) atm, \(P_{H_2O}=40.2\) atm into the formula:

$$
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First, calculate \((14.2)^4 = 14.2\times14.2\times14.2\times14.2=4103.8816\), \((40.2)^6=(40.2)^2\times(40.2)^2\times(40.2)^2=(1616.04)\times(1616.04)\times(1616.04)=4.199\times10^{9}\), \((17.5)^4 = 17.5\times17.5\times17.5\times17.5 = 93789.0625\), \((60.2)^5=60.2\times60.2\times60.2\times60.2\times60.2 = 7.84\times10^{8}\)

$$
LATEXBLOCK1
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Step3: Calculate the value

\(K_p\approx0.23\)

Answer:

\(0.23\)