Question

after growing tired of squinting while driving, desmond went shopping for a pair of sunglasses. he tried on glasses with different frames and lenses.

	cat eye frames	browline frames	aviator frames
regular lenses	7	4	8

what is the probability that a randomly selected pair of sunglasses has cat eye frames and does not have regular lenses?

simplify any fractions.

Explanation:

Step1: Calculate the total number of sunglasses

Add up all the values in the table: \(2 + 8+7+7 + 4+8=36\)

Step2: Find the number of cat - eye frames without regular lenses

The number of cat - eye frames without regular lenses (i.e., with polarized lenses) is \(2\)

Step3: Calculate the probability

The probability \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{2}{36}=\frac{1}{18}\)

Answer:

\(\frac{1}{18}\)