Question

action balanced equation particle view (draw what you see in the white boxes) balance view (draw what you see in the balances) make ammonia _ n₂ + _ h₂ → _ nh₃

Explanation:

Step1: Count atoms on both sides

For \(N\): Left - \(2\) (from \(N_2\)), Right - \(1\) (from \(NH_3\)). For \(H\): Left - \(2\) (from \(H_2\)), Right - \(3\) (from \(NH_3\)).

Step2: Balance \(N\) atoms

Put a coefficient of \(2\) in front of \(NH_3\): \(N_2+ H_2
ightarrow 2NH_3\). Now \(N\) is balanced (\(2\) on both sides).

Step3: Balance \(H\) atoms

Now for \(H\): Right has \(6\) (\(2\times3\) in \(2NH_3\)). So put a coefficient of \(3\) in front of \(H_2\): \(N_2 + 3H_2
ightarrow 2NH_3\).

Answer:

\(1N_2+3H_2
ightarrow 2NH_3\)