Question

acid base

1. some household ammonia cleaning solution has a ph of 11.35. therefore, the hydroxide ion concentration is a.bc × 10^-d. the values of a, b, c and d are

and
(record your answer in the numerical - response section below.)
your answer: prev next

Explanation:

Step1: Calculate pOH

We know that \(pH + pOH=14\). Given \(pH = 11.35\), then \(pOH=14 - 11.35=2.65\).

Step2: Calculate \([OH^{-}]\)

The formula for \(pOH\) is \(pOH=-\log[OH^{-}]\). So, \([OH^{-}]=10^{-pOH}\). Substituting \(pOH = 2.65\), we get \([OH^{-}]=10^{- 2.65}\).
Using the property \(a^{m + n}=a^{m}\times a^{n}\), \(10^{-2.65}=10^{-3 + 0.35}=10^{0.35}\times10^{-3}\).
Since \(10^{0.35}\approx2.24\) (because \(10^{0.3}\approx2\) and \(10^{0.4}\approx2.5\)), \([OH^{-}]\approx2.24\times10^{-3}\).

Answer:

\(2\), \(2\), \(4\), \(3\)