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Question
- according to lewis dot theory, the nitride anion will have _ i _ valence electrons, and _ ii _ bonding electrons. the statement above is best completed by information in row
Step1: Determine the valence electrons of Nitride anion
Nitrogen has 5 valence electrons. Nitride anion is \(N^{3 -}\). The extra 3 electrons (due to - 3 charge) are added to the valence electrons. So the total valence electrons \(=5 + 3=8\).
Step2: Determine the bonding electrons
Nitride anion \(N^{3 -}\) has a complete octet (8 electrons). In Lewis dot structure, for \(N^{3 -}\), there are no bonds formed (it is a simple anion). So the number of bonding electrons is \(0\).
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First row (8, 0)