Question

if the above quantum numbers describe two different electrons in an oxygen atom, and the angular momentum number x is 1, what is the possible number of y? _

Explanation:

Step1: Recall quantum number rules

For a given principal quantum number \(n\), the angular - momentum quantum number \(l\) (here \(X\) and \(Y\)) can take values \(l = 0,1,\cdots,n - 1\). Given \(n=2\), so \(l\) can be \(0\) or \(1\).

Step2: Determine the value of \(Y\)

Since \(X = 1\), and the two electrons are different. The possible values of \(l\) (angular - momentum quantum number) for \(n = 2\) are \(0\) and \(1\). To be different from \(X=1\), \(Y = 0\)

Answer:

\(0\)