Question

a1 | player 1 player 2 ladainian tomlinson 3 michael turner 4 lorenzo neal 5 philip rivers 6 andrew pinnock 7 erick parker 8 vincent jackson 9 charlie whitehurst 10 keenan mccardell 11 brandon manumaleuna 12 billy valek 13 14 mike scifres 15 16 17 18 median for #1 19 median for #3 20 21 mean for #1 22 mean for #3 23 24 b rushing yards 1815 202 140 49 25 19 16 13 8 1 -3 -7 c rushing yards 1815 202 140 49 25 19 16 13 8 1 -3 -7 d e city columbia silver spring dundalk wheaton - glenmont ellicott city germantown bethesda frederick gaithersburg cumberland f population 88,254 76,540 62,306 57,694 56,397 55,419 55,277 52,816 52,455 8,736 median for #5 median for #6 mean for #5 mean for #6

Explanation:

Step1: Identify Data for Rushing Yards (Column B)

List the rushing yards values from column B: 1815, 202, 140, 49, 25, 19, 16, 13, 8, 1, -3, -7. Sort them: -7, -3, 1, 8, 13, 16, 19, 25, 49, 140, 202, 1815.

Step2: Calculate Median for #1 (Column B)

There are 12 values (even count). Median is average of 6th and 7th terms: $\frac{16 + 19}{2} = 17.5$.

Step3: Identify Data for Rushing Yards (Column C)

Same as column B, so median is also 17.5.

Step4: Identify Population Data (Column F)

Values: 88254, 76540, 62306, 57694, 56397, 55419, 55277, 52816, 52455, 8736. Sort them: 8736, 52455, 52816, 55277, 55419, 56397, 57694, 62306, 76540, 88254.

Step5: Calculate Median for #5 (Column F)

10 values (even count). Median is average of 5th and 6th terms: $\frac{55419 + 56397}{2} = 55908$.

Step6: Calculate Median for #6 (Column F)

Same sorted list, median is 55908 (wait, no—wait, original data for #6? Wait, column F has 10 values? Wait, rows 3 - 12: 10 cities? Wait, row 3: Columbia (88254), row 4: Silver Spring (76540), row 5: Dundalk (76540? No, row 5: Dundalk 76540? Wait, original data:

Row 3: Columbia 88,254

Row 4: Silver Spring 76,540

Row 5: Dundalk 76,540? No, row 5: Dundalk 76,540? Wait, no, the table:

E3: Columbia, F3: 88,254

E4: Silver Spring, F4: 76,540

E5: Dundalk, F5: 76,540? Wait, no, F5 is 76,540? Wait, original F column:

F3: 88254, F4:76540, F5:62306? Wait, no, the user's table:

E3: Columbia, F3: 88,254

E4: Silver Spring, F4: 76,540

E5: Dundalk, F5: 76,540? No, looking back:

Wait, the F column:

Row 3: 88,254

Row 4: 76,540

Row 5: 62,306

Row 6: 57,694

Row 7: 56,397

Row 8: 55,419

Row 9: 55,277

Row 10: 52,816

Row 11: 52,455

Row 12: 8,736

Ah, 10 values. So sorted: 8736, 52455, 52816, 55277, 55419, 56397, 57694, 62306, 76540, 88254. So 10 values, median is (5th + 6th)/2 = (55419 + 56397)/2 = 55908.

Step7: Calculate Mean for #1 (Column B)

Sum: -7 + (-3) + 1 + 8 + 13 + 16 + 19 + 25 + 49 + 140 + 202 + 1815 = Let's calculate:

Negative: -10. Positive: 1+8=9, +13=22, +16=38, +19=57, +25=82, +49=131, +140=271, +202=473, +1815=2288. Total sum: 2288 - 10 = 2278. Mean: $\frac{2278}{12} \approx 189.83$.

Step8: Mean for #3 (Column C)

Same as column B, so mean ≈ 189.83.

Step9: Calculate Mean for #5 (Column F)

Sum: 88254 + 76540 + 62306 + 57694 + 56397 + 55419 + 55277 + 52816 + 52455 + 8736. Let's sum:

88254 + 76540 = 164794; +62306 = 227100; +57694 = 284794; +56397 = 341191; +55419 = 396610; +55277 = 451887; +52816 = 504703; +52455 = 557158; +8736 = 565894. Mean: $\frac{565894}{10} = 56589.4$.

Step10: Mean for #6 (Column F)

Same as #5, so mean is 56589.4.

Answer:

Median for #1 (Column B): 17.5
Median for #3 (Column C): 17.5
Median for #5 (Column F): 55908
Median for #6 (Column F): 55908
Mean for #1 (Column B): ≈189.83
Mean for #3 (Column C): ≈189.83
Mean for #5 (Column F): 56589.4
Mean for #6 (Column F): 56589.4