Question

3.87×10²² zinc atoms
m =
g

Explanation:

Step1: Recall Avogadro's number and molar mass of Zn

Avogadro's number is \( 6.022\times10^{23}\) atoms/mol, and molar mass of Zn is \( 65.38\) g/mol.

Step2: Calculate moles of Zn atoms

Moles (\(n\)) = number of atoms / Avogadro's number. So \(n=\frac{3.87\times10^{22}}{6.022\times10^{23}\text{ atoms/mol}}\).

Step3: Calculate mass of Zn

Mass (\(m\)) = moles × molar mass. So \(m = n\times65.38\) g/mol. Substitute \(n\): \(m=\frac{3.87\times10^{22}}{6.022\times10^{23}}\times65.38\).
Calculate \(\frac{3.87\times10^{22}}{6.022\times10^{23}}\approx0.06426\) mol. Then \(m = 0.06426\times65.38\approx4.20\) g.

Answer:

\(4.20\)